| ⇦ | 
| ⇨ |
Among the following the compound that is readily soluble in water is
Options
(a) BeSO₄
(b) CaSO₄
(c) SrSO₄
(d) BaSO₄
Correct Answer:
BeSO₄
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - HSO₄⁻ + OH⁻ → SO₄²⁻ + H₂O. which is correct about conjugate acid – base pair
- The compound which does not exist as hydrate form
- Hardness of water due to presence of salts of
- Which metal will displace copper from copper sulphate solution
- Glycerol on treated with oxalic acid gives
Topics: S and Some P Block Elements
(157)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- HSO₄⁻ + OH⁻ → SO₄²⁻ + H₂O. which is correct about conjugate acid – base pair
- The compound which does not exist as hydrate form
- Hardness of water due to presence of salts of
- Which metal will displace copper from copper sulphate solution
- Glycerol on treated with oxalic acid gives
Topics: S and Some P Block Elements (157)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply