| ⇦ | 
| ⇨ |
Allyl chloride on dehydrochlorination gives
Options
(a) propadiene
(b) propylene
(c) allyl alcohol
(d) acetone
Correct Answer:
propadiene
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Bond order of 1.5 is shown by:
- What is the number of mols of hydrogen atoms in 3.2g of methane
- The number of moles of KMnO₄ reduced by one mole of KI in alkaline medium is
- Which of the following does not acts as Lewis acid
- The raw materials for the commercial manufacture of DDT are
Topics: Haloalkenes and Haloarenes
(78)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Bond order of 1.5 is shown by:
- What is the number of mols of hydrogen atoms in 3.2g of methane
- The number of moles of KMnO₄ reduced by one mole of KI in alkaline medium is
- Which of the following does not acts as Lewis acid
- The raw materials for the commercial manufacture of DDT are
Topics: Haloalkenes and Haloarenes (78)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Dehydro chlorination means one hydrogen and one chlorine is removed from the allylic carbon so two double bond is formed between the two carbon and propadiene is formed
Dehydrochlorination means removal of one hydrogen and one chlorine.. So double bond is formed in between the carbon atom
CH2=C-C-Cl—-C=C=C