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A wire of resistance 4 ohm is stretched to twice its original length. The resistance of stretched wire would be
Options
(a) 4Ω
(b) 8Ω
(c) 16Ω
(d) 2Ω
Correct Answer:
16Ω
Explanation:
Resistance R = ρℓ / A
ℓ’ = 2 ℓ ⇒ A’ = A / 2
R’ = ρ [2 ℓ / (A / 2)] = 4R = 4 × 4Ω = 16Ω
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Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A magnetic needle suspended parallel to a magnetic field requires √3J of work
- The masses of three wires of copper are in the ratio 1:3:5 and lengths
- The total energy of a particle executing SHM is 80 J
- The nuclear radius of a certain nucleus is 7.2 fm and it has a charge of 1.28×10⁻¹⁷ C.
- Radius of first orbit of the electron in a hydrogen atom is 0.53 Å. So the radius
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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