| ⇦ | 
| ⇨ |
A uniform rod of length l is placed with one end in contact with the horizontal and is then inclined at an angle α to the horizontal and allowed to fall, without slipping at contact point. When it becomes horizontal, its angular velocity will be
Options
(a) ? = √3gsin α/l
(b) ? = √2l/3gsin α
(c) ? = √6gsin α/l
(d) ? = √l/gsin α
Correct Answer:
? = √3gsin α/l
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A cell can be balanced against 110 cm and 100 cm of potentiometer wire, respectively
- Two parallel beams of positron moving in the same direction will
- A particle of mass ‘m’ is kept at rest at a height 3R from the surface of earth
- If critical angle for a material to air passage is 30°, the refractive index
- A certain number of spherical dropes of a liquid of radius r coalesce to form a single
Topics: Motion of system of Particles and Rigid Body
(73)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A cell can be balanced against 110 cm and 100 cm of potentiometer wire, respectively
- Two parallel beams of positron moving in the same direction will
- A particle of mass ‘m’ is kept at rest at a height 3R from the surface of earth
- If critical angle for a material to air passage is 30°, the refractive index
- A certain number of spherical dropes of a liquid of radius r coalesce to form a single
Topics: Motion of system of Particles and Rigid Body (73)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply