| ⇦ | 
| ⇨ |
A thin circular ring of mass M and radius R rotates about an axis through its centre and perpendicular to its plane, with a constant angular velocity ?. Four small spheres each of mass m (negligible radius) are kept gently to the opposite ends of two mutually perpendicular diameters of the ring. The new angular velocity of the ring will be
Options
(a) M?/4m
(b) [M+4m/M] ?
(c) [M/M-4m] ?
(d) [M/M+4m] ?
Correct Answer:
[M/M+4m] ?
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions:
- The height of the dam, in an hydroelectric power station is 10 m. In order to generate
- A ball rolls off the top of stair way with a horizontal velocity of magnitude 1.8 m/s
- An electric dipole is placed at an angle 30°with an electric field intensity 2×10⁵N/C.
- Alternating current is transmitted to distant places at
- The Davisson- Germer experiment is the direct evidence of
Topics: Motion of system of Particles and Rigid Body
(73)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply