| ⇦ |
| ⇨ |
A spring of spring constant 5 x 10³ N/m is stretched initially by 5 cm from the unstretched position. The work required to stretch it further by another 5 cm is
Options
(a) 18.75 N-m
(b) 12.5 N-m
(c) 6.25 N-m
(d) 25 N-m
Correct Answer:
18.75 N-m
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The potential energy of a simple harmonic oscillator when the particle is half way
- The angular velocity of second’s hand of a watch is
- λ₁ and λ₂ are used to illuminate the slits. β₁ and β₂ are the corresponding fringe
- The dimensional formula of Plancks’s constant and angular momentum are
- The temperature coefficient of a resistance wire is 0.00125 per degree.
Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The potential energy of a simple harmonic oscillator when the particle is half way
- The angular velocity of second’s hand of a watch is
- λ₁ and λ₂ are used to illuminate the slits. β₁ and β₂ are the corresponding fringe
- The dimensional formula of Plancks’s constant and angular momentum are
- The temperature coefficient of a resistance wire is 0.00125 per degree.
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply