⇦ | ![]() | ⇨ |
A source of light is placed at a distance of 50 cm from a photocell and the stopping potential is found to be V₀. If the distance between the light source and photocell is made 25 cm, the new stopping potential will be
Options
(a) 2V₀
(b) V₀ / 2
(c) V₀
(d) 4V₀
Correct Answer:
V₀
Explanation:
Since, stopping potential is independent of distance hence new stopping potential will remain unchanged i.e., new stopping potential = V₀.
Related Questions:
- A satellite S is moving in an elliptical orbit around the earth. The mass
- A body moves with a uniform acceleration a and zero initial velocity
- A bullet emerges from a barrel of length 1.2 m with a speed of 640 ms⁻¹.
- The number of NAND gates required to form an AND gate is
- A boy whirls a stone in a horizontal circle of radius 1.5 m and at height 2.0 m
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply