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A source of light is placed at a distance of 50 cm from a photocell and the stopping potential is found to be V₀. If the distance between the light source and photocell is made 25 cm, the new stopping potential will be
Options
(a) 2V₀
(b) V₀ / 2
(c) V₀
(d) 4V₀
Correct Answer:
V₀
Explanation:
Since, stopping potential is independent of distance hence new stopping potential will remain unchanged i.e., new stopping potential = V₀.
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Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The Boolean expression P+ P ̅ Q, where P and Q are the inputs of the logic
- Three resistances 2Ω, 3Ω and 4Ω are connected in parallel. The ratio of currents passing
- The ratio of the acceleration for a solid sphere(mass m and radius R)rolling down
- Activity of a radioactive sample decreases to (1/3)rd of its original value
- A body of mass m is thrown upwards at an angle θ with the horizontal with velocity
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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