⇦ | ⇨ |
A source of light is placed at a distance of 50 cm from a photocell and the stopping potential is found to be V₀. If the distance between the light source and photocell is made 25 cm, the new stopping potential will be
Options
(a) 2V₀
(b) V₀ / 2
(c) V₀
(d) 4V₀
Correct Answer:
V₀
Explanation:
Since, stopping potential is independent of distance hence new stopping potential will remain unchanged i.e., new stopping potential = V₀.
Related Questions: - If the feedback voltage is increased in a negative feedback amplifier, then
- A galvanometer of resistance 50Ω is connected to a battery of 3 V along with a resistance
- From a disc of radius R, a concentric circular portion of radius r is cut-out so
- A condenser of 250 μF is connected in parallel to a coil of inductance of 0.16 mH
- A block of mass 4 kg is kept on a rough horizontal surface.The coefficient of static
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If the feedback voltage is increased in a negative feedback amplifier, then
- A galvanometer of resistance 50Ω is connected to a battery of 3 V along with a resistance
- From a disc of radius R, a concentric circular portion of radius r is cut-out so
- A condenser of 250 μF is connected in parallel to a coil of inductance of 0.16 mH
- A block of mass 4 kg is kept on a rough horizontal surface.The coefficient of static
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply