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A solution containing 6 g urea per litre is isotonic with a solution containing
Options
(a) 5.85 g NaCl per litre
(b) 34.2 g sucrose per litre
(c) 36.0 g glucose per litre
(d) 6.0 g sucrose per litre
Correct Answer:
34.2 g sucrose per litre
Explanation:
For isotonic solution, C₁ = C₂ or , n₁ / M₁V₁ = n₂ / M₂V₂.
Given, n₁ / M₁V₁ = 6/60 = 1/10.
For 34.2 g sucrose per litre C₂ = 34.2/342 = 1/10 . i.e. C₁ = C₂ .
Related Questions: - The electronic configuration of transition elements is exhibited by
- Schiff’s reagent is
- α-D-glucose and β-D-glucose are
- Which of the following shows linear structure
- Treatment of a mixture of CH₃Cl and C₂H₅Cl with sodium in dry ether can generat
Topics: Solid State and Solutions
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The electronic configuration of transition elements is exhibited by
- Schiff’s reagent is
- α-D-glucose and β-D-glucose are
- Which of the following shows linear structure
- Treatment of a mixture of CH₃Cl and C₂H₅Cl with sodium in dry ether can generat
Topics: Solid State and Solutions (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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Let wt.of sugar =w g per litre
Both will have same osmotic pressure.
Therefore,
w×R×T=6÷50× RT÷ 1
w= 34.2 g per litre