Navigate

A rod of weight W is supported by two parallel knife edge A and B

A rod of weight W is supported by two parallel knife edge A and B and is in equilibrium, in a horizontal position.The knives are at a distance d from each other.The centre of mass of the rod is at distance x from A.The normal reaction on A is

Options

(a) Wd/x
(b) W(d-x) / x
(c) W(d-x) / d
(d) Wx / d

Correct Answer:

W(d-x) / d

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

admin:

Related Questions

  1. In Young’s double slit experiment, a third slit is made in between the double slits.
  2. The mean distance between the atoms of iron is 3 x 10⁻¹⁰ m and interatomic force
  3. A particle with total energy E is moving in a potential energy region U(x)
  4. To get three images of single object, one should have two plane mirrors at an angle of
  5. If the terminal speed of a sphere of gold (density=19.5 kg/m³) is 0.2 m/s