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A rod of weight W is supported by two parallel knife edge A and B and is in equilibrium, in a horizontal position.The knives are at a distance d from each other.The centre of mass of the rod is at distance x from A.The normal reaction on A is
Options
(a) Wd/x
(b) W(d-x) / x
(c) W(d-x) / d
(d) Wx / d
Correct Answer:
W(d-x) / d
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Motion of system of Particles and Rigid Body
(73)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The bandgap in Germanium and silicon, in eV, are respectively
- A body travels 200 cm in the first two seconds and 220 cm in the next 4 secs
- The radius of a nucleus of mass number A is directly proportional to
- A thin semicircular conducting ring (PQR) of radius r is falling with its plane
- If A.B=A x B,then the angle between A and B is
Topics: Motion of system of Particles and Rigid Body (73)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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