⇦ | ⇨ |
A proton of mass m and charge q is moving in a plane with kinetic energy E. If there exists a uniform magnetic field B, perpendicular to the plane motion, the proton will move in a circular path of radius
Options
(a) 2Em/qB
(b) √2Em/qB
(c) √Em/2qB
(d) √2Eq/qB
Correct Answer:
√2Em/qB
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - If v is the speed of sound in air, then the shortest length of the closed pipe
- A concave lens of focal length f forms an image which is 1/3 times the size
- Water rises in a vertical capillary tube up to a height of 2.0 cm.
- A charged oil drop is suspended in a uniform field at 3×10⁴ V/m so that it neither falls
- The energy of groundstate (n=1) of hydrogen level is -13.6 eV. The ionistation
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If v is the speed of sound in air, then the shortest length of the closed pipe
- A concave lens of focal length f forms an image which is 1/3 times the size
- Water rises in a vertical capillary tube up to a height of 2.0 cm.
- A charged oil drop is suspended in a uniform field at 3×10⁴ V/m so that it neither falls
- The energy of groundstate (n=1) of hydrogen level is -13.6 eV. The ionistation
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply