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A proton of mass m and charge q is moving in a plane with kinetic energy E. If there exists a uniform magnetic field B, perpendicular to the plane motion, the proton will move in a circular path of radius
Options
(a) 2Em/qB
(b) √2Em/qB
(c) √Em/2qB
(d) √2Eq/qB
Correct Answer:
√2Em/qB
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Four cells, each of emf E and internal resistance r, are connected in series across
- If A=4i+4j+4k and b=3i+j+4k, then angle between vectors A and B is
- A solid cylinder of mass M and radius R rolls without slipping down and inclined plane
- The velocity of a particle at an instant is 10 ms⁻¹.After 3 s its velocity will become
- Weight of a body of mass m decreases by 1% when it is raised to height h
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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