| ⇦ | 
| ⇨ |
A proton of mass 1.6×10⁻²⁷ kg goes round in a circular orbit of radius 0.10 m under a centripetal force of 4×10⁻¹³ N. The frequency of revolution of the proton is about
Options
(a) 0.08×10⁸ cps
(b) 4×10⁸ cps
(c) 8×10⁸ cps
(d) 12×10⁸ cps
Correct Answer:
0.08×10⁸ cps
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions:
- A body of length 1 m having cross-sectional area 0.75 m² has heat flow through it
- A deutron is bombarded on ₈O¹⁶ nucleus and α-particle is emitted. The product nucleus is
- The electric vector vibration of an electromagnetic wave is given by
- An α-particle and a proton are accelerated through same potential difference
- When sound is produced in an aeroplane with a velocity of 200 m/s horizontally,
Topics: Motion in Plane
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply