| ⇦ | 
| ⇨ |
A potentiometer wire of length 10 m and resistance 10 Ω per metre is connected in series with a resistance box and a 2 volt battery. If a potential difference of 100mV is balanced across the whole length of potentiometer wire, then the resistance introduced in the resistance will be
Options
(a) 1900Ω
(b) 900Ω
(c) 190Ω
(d) 90Ω
Correct Answer:
190Ω
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A 1Ω resistance in series with an ammeter is balanced by 75 cm of potentiometer wire
- Two thin dielectric slabs of dielectric constants K₁ and K₂, (K₁ < K₂) are inserted
- The ionization energy of Li⁺⁺ is equal to
- A small rod of bismuth is suspended freely between the poles of a strong electromagnet.
- A body is moving in a vertical circle. The string must remain taut at the highest point
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A 1Ω resistance in series with an ammeter is balanced by 75 cm of potentiometer wire
- Two thin dielectric slabs of dielectric constants K₁ and K₂, (K₁ < K₂) are inserted
- The ionization energy of Li⁺⁺ is equal to
- A small rod of bismuth is suspended freely between the poles of a strong electromagnet.
- A body is moving in a vertical circle. The string must remain taut at the highest point
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply