| ⇦ | 
| ⇨ |
A particle of mass m is projected with velocity v making an angle of 45° with the horizontal. When the particle lands on the level ground the magnitude of the change in its momentum will be:
Options
(a) 2mv
(b) mv/√2
(c) mv√2
(d) zero
Correct Answer:
mv√2
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - If 10000 V is applied across an X-ray tube, what will be the ratio of de-Broglie
- The value of Planck’s constant is
- The electric potential V at any point (x,y,z) all in meters in space is given by
- If voltage across a bulb rated 220 volt-100 Watt drops by 2.5% of its rated value
- Ionization potential of hydrogen atom is 13.6 eV. Hydrogen atoms in the ground state
Topics: Motion in Plane
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If 10000 V is applied across an X-ray tube, what will be the ratio of de-Broglie
- The value of Planck’s constant is
- The electric potential V at any point (x,y,z) all in meters in space is given by
- If voltage across a bulb rated 220 volt-100 Watt drops by 2.5% of its rated value
- Ionization potential of hydrogen atom is 13.6 eV. Hydrogen atoms in the ground state
Topics: Motion in Plane (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply