| ⇦ | 
| ⇨ |
A particle of mass m executes simple harmonic motion with amplitude a and frequency v. The average kinetic energy during its motion from the position of equilibrium to the end is
Options
(a) 2 π² m a² v²
(b) π² m a² v²
(c) m a² v² / 4
(d) 4 π² m a² v²
Correct Answer:
π² m a² v²
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Three cells, each of e.m.f 1.5 V and internal resistance 1 ohm are connected in parallel
- If energy(E), velocity(V) and time(T) are chosen as fundamental quantities,
- Two bubbles A and B (A>B) are joined through a narrow tube. Then
- In the relation n=PV/RT, n stands for
- A body of mass M hits normally a rigid wall with velocity V and bounces back
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Three cells, each of e.m.f 1.5 V and internal resistance 1 ohm are connected in parallel
- If energy(E), velocity(V) and time(T) are chosen as fundamental quantities,
- Two bubbles A and B (A>B) are joined through a narrow tube. Then
- In the relation n=PV/RT, n stands for
- A body of mass M hits normally a rigid wall with velocity V and bounces back
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply