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A particle of mass m executes simple harmonic motion with amplitude a and frequency v. The average kinetic energy during its motion from the position of equilibrium to the end is
Options
(a) 2 π² m a² v²
(b) π² m a² v²
(c) m a² v² / 4
(d) 4 π² m a² v²
Correct Answer:
π² m a² v²
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- 1 a.m.u. is equivalent to
- If ∆Q>0 when heat flows into a system, ∆W>0 when work is done on the system
- The mean radius of the earth is R, its angular speed on its own axis is ?
- The two ends of a rod of length L and a uniform cross-sectional area
- The binding energy per nucleon of ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06MeV
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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