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A particle moves along with x-axis.The position x of particle with respect to time t from origin is given by x=bₒ+b₁t+b₂t².The acceleration of particle is
Options
(a) bₒ
(b) b₁
(c) b₂
(d) 2b₂
Correct Answer:
2b₂
Explanation:
Given, x=b₀+b₁t+b₂t²
Also, v=dx/dt=d/dt(b₀+b₁t+b₂t²)
Using (d/dx).xⁿ=nxⁿ⁻¹, we have
v=b₁+2b₂t
The Acceleration is,
a=dv/dt=d/dt(b₁+2b₂t)
=2b₂
Another Explanation:
Distance , x = b₀ + b₁t + b₂t²
velocity , v = (dx / dt ) = b₁ + 2b₂t
Acceleration, α = d²x / dt² = 2 b₂.
Related Questions: - In an astronomical telescope in normal adjustment a straight black line of length
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Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In an astronomical telescope in normal adjustment a straight black line of length
- When a bullet of mass 10 g and speed 100 ms⁻¹ penetrates up to distance 1 cm
- A particle moves from position r₁ = 3i + 2j -6k to position r₂ = 14i + 13 j+ 9 k
- A plumb line is suspended form a ceiling of a car moving with horizontal acceleration
- The charges Q, +q, and +q are placed at the vartices of an equilateral
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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