| ⇦ | 
| ⇨ |
A magnet of length 10 cm and magnetic moment 1 A-m² is placed along the side AB of an equilateral triangle ABC. If length of side AB is 10 cm the magnetic induction at the point C is (µₒ=4 π x 10⁻⁷ H/m)
Options
(a) 10⁻⁹ T
(b) 10⁻⁷ T
(c) 10⁻⁵ T
(d) 10⁻⁴ T
Correct Answer:
10⁻⁴ T
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Angular momentum of the particle rotating with a central force is constant due to
- A train moving at a speed of 220 ms⁻¹ towards a stationary object
- The binding energy per nucleon of ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06MeV
- A projectile is thrown in the upward direction making an angle of 60°with the horizontal
- The radius of curvature of a convave mirror is 24 cm and the imager is magnified
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Angular momentum of the particle rotating with a central force is constant due to
- A train moving at a speed of 220 ms⁻¹ towards a stationary object
- The binding energy per nucleon of ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06MeV
- A projectile is thrown in the upward direction making an angle of 60°with the horizontal
- The radius of curvature of a convave mirror is 24 cm and the imager is magnified
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply