| ⇦ | 
| ⇨ |
A ideal gas will have maximum density when
Options
(a) p = 1 atm, T = 300 K
(b) p = 2 atm,T = 150 K
(c) p = 0.5 atm,T = 600 K
(d) p = 1.0 atm , T = 500 K
Correct Answer:
p = 2 atm,T = 150 K
Explanation:
An ideal gas will have maximum density at high pressure and low temperature i.e. when P = 2 atm, T = 150 K.
Related Questions: - 116 mg of a compound on vaporisation in a Victor Meyer’s apparatus displaces
- Heat of combustion ΔH for C(s) , H₂(g)and CH₄(g) are -94, -68 and -213 kcal/mol.
- In the van der Waals equation, ‘a’ signifies
- When KMnO₄ reacts with KBr in alkaline medium gives bromate ion. Then oxidation
- The ore horn silver corresponds to
Topics: States of Matter Gases and Liquids
(80)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- 116 mg of a compound on vaporisation in a Victor Meyer’s apparatus displaces
- Heat of combustion ΔH for C(s) , H₂(g)and CH₄(g) are -94, -68 and -213 kcal/mol.
- In the van der Waals equation, ‘a’ signifies
- When KMnO₄ reacts with KBr in alkaline medium gives bromate ion. Then oxidation
- The ore horn silver corresponds to
Topics: States of Matter Gases and Liquids (80)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
PV=nRT pv=W/m RT. P=W/v RT/m P=dRT/m since W/v= d and d=mp/RT so here at high pressure and low temp ,p=2, and t=150 are suitable in given options