| ⇦ | 
| ⇨ |
A galvanometer coil has a resistance of 15 ohm and gives full scale deflection for a current of 4 mA. To convert it to an ammeter of range 0 to 6 A,
Options
(a) 10 mΩ resistance is to be connected in parallel to the galvanometer
(b) 10 mΩ resistance is to be connected in series with the galvanometer
(c) 0.1 Ω resistance is to be connected in parallel to the galvanometer
(d) 0.1 Ω resistance is to be connected in series with the galvanometer
Correct Answer:
10 mΩ resistance is to be connected in parallel to the galvanometer
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Which of the following measurement is most precise?
- In photoelectric effect, the photoelectric current
- The electric potential at a point in free space due to a charge Q coulomb is Q x 10¹¹ v
- A closely wound solenoid of 2000 turns and area of cross-section 1.5 x 10⁻⁴ m² carries
- A boy is trying to start a fire by focusing sunlight on a piece of paper using
Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following measurement is most precise?
- In photoelectric effect, the photoelectric current
- The electric potential at a point in free space due to a charge Q coulomb is Q x 10¹¹ v
- A closely wound solenoid of 2000 turns and area of cross-section 1.5 x 10⁻⁴ m² carries
- A boy is trying to start a fire by focusing sunlight on a piece of paper using
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Given :-
G=15ohm Ig=4mA =0.004A.
I=6A. A shunt resistor of resistance S is to be connected in parallel with the galvanometer to convert it into an ammeter . The value of S is given by – S = Ig×G / I-Ig.
= 0.004 ×15 / 6-0.004. S= 0.06/5.996 = 0.01ohm =10m ohm.