| ⇦ |
| ⇨ |
A force F=ai+3j+6k is acting at a point r=2i-6j-12k. The value of α for which angular momentum about origin is conserved is
Options
(a) 2
(b) zero
(c) 1
(d) -1
Correct Answer:
-1
Explanation:
From Newton’s second law for rotational motion,
τ = dL / dt, if L = constant then τ = 0
So, τ = r × F = 0
(2î – 6ĵ – 12k̂) × (αî + 3ĵ + 6k̂) = 0
Solving we get α = -1.
Related Questions: - A man of 50 kg mass is standing in a gravity free space at a height
- The electron of a hydrogen atom revolves round the proton in a circular
- Choose the correct statement
- In which case positive work has to be done in seperating them?
- A conducting square frame of side ‘a’ and a long straight wire carrying current I
Topics: Motion of system of Particles and Rigid Body
(73)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A man of 50 kg mass is standing in a gravity free space at a height
- The electron of a hydrogen atom revolves round the proton in a circular
- Choose the correct statement
- In which case positive work has to be done in seperating them?
- A conducting square frame of side ‘a’ and a long straight wire carrying current I
Topics: Motion of system of Particles and Rigid Body (73)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply