| ⇦ |
| ⇨ |
A disc of mass 100 g is kept floating horizontally in air by firing bullets, each of mass 5g with the same velocity at the same rate of 10 bullets/s.The bullets rebound with the same speed in opposite direction,the velocity of each bullet at the time of impact is
Options
(a) 196 cms⁻¹
(b) 9.8 cms⁻¹
(c) 98 cms⁻¹
(d) 980 cm⁻¹
Correct Answer:
980 cm⁻¹
Explanation:
Rate of change in momentum of the bullets balances weight of the plate
2m’vn = mg
.·. v = mg/2m’n = (100 x 980)/(2 x 5 x 10)
= 980 cm⁻¹
Related Questions: - Which of the following rods of same material undergoes maximum elongation
- Potential at a point x-distance from the centre inside the conducting sphere
- A series combination of n₁ capacitors, each of value C₁, is charged by a source
- A particle of mass M is executing oscillations about the origin on the x-axis.
- A transistor is working in common emitter mode. Its amplification factor is 80
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following rods of same material undergoes maximum elongation
- Potential at a point x-distance from the centre inside the conducting sphere
- A series combination of n₁ capacitors, each of value C₁, is charged by a source
- A particle of mass M is executing oscillations about the origin on the x-axis.
- A transistor is working in common emitter mode. Its amplification factor is 80
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply