| ⇦ | 
| ⇨ |
A current of 2A flows through a 2Ω resistor when connected across a battery. The same battery supplies a current of 0.5A when connected across a 9Ω resistor. The internal resistance of the battery is
Options
(a) 0.5Ω
(b) 1/3Ω
(c) 1/4Ω
(d) 1Ω
Correct Answer:
1/3Ω
Explanation:
Let the internal resistance of the battery be r. Then the current flowing through the circuit is given by
i = E / R + r
In first case, 2 = E / 2 + r …(i)
In second case, 0.5 = E / 9 + r … (ii)
From (i) & (ii), 4 + 2r = 4.5 + 0.5r
1.5r = 0.5
r = 1/3Ω
Related Questions: - A spring of spring constant 5 x 10³ N/m is stretched initially by 5 cm
- A transformer having efficiency of 90% is working on 200 V and 3kW power supply
- A proton carrying 1 MeV kinetic energy is moving in a circular path of radius
- If the red light is replaced by blue light illuminating the object in a microscope
- A spherical drop of capacitance 1μF is broken into eight drops of equal radius.
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A spring of spring constant 5 x 10³ N/m is stretched initially by 5 cm
- A transformer having efficiency of 90% is working on 200 V and 3kW power supply
- A proton carrying 1 MeV kinetic energy is moving in a circular path of radius
- If the red light is replaced by blue light illuminating the object in a microscope
- A spherical drop of capacitance 1μF is broken into eight drops of equal radius.
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply