| ⇦ | 
| ⇨ |
A current of 2A flows through a 2Ω resistor when connected across a battery. The same battery supplies a current of 0.5A when connected across a 9Ω resistor. The internal resistance of the battery is
Options
(a) 0.5Ω
(b) 1/3Ω
(c) 1/4Ω
(d) 1Ω
Correct Answer:
1/3Ω
Explanation:
Let the internal resistance of the battery be r. Then the current flowing through the circuit is given by
i = E / R + r
In first case, 2 = E / 2 + r …(i)
In second case, 0.5 = E / 9 + r … (ii)
From (i) & (ii), 4 + 2r = 4.5 + 0.5r
1.5r = 0.5
r = 1/3Ω
Related Questions: - MA⁻¹T⁻² is the dimensional formula of
- The difference in the variation of resistance with temperature in a metal
- According to Hook’s law of elasticity, if stress is increased, the ratio of stress
- A block of mass 0.50 kg is moving with a speed of 2.00 ms⁻¹ on a smooth surface.
- A particle moving in a straight line covers half the distance with speed of 3 m/s
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- MA⁻¹T⁻² is the dimensional formula of
- The difference in the variation of resistance with temperature in a metal
- According to Hook’s law of elasticity, if stress is increased, the ratio of stress
- A block of mass 0.50 kg is moving with a speed of 2.00 ms⁻¹ on a smooth surface.
- A particle moving in a straight line covers half the distance with speed of 3 m/s
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply