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A charged particle with a velocity 2×10³ ms⁻¹ passes undeflected through electric field and magnetic fields in mutually perpendicular directions. The magnetic field is 1.5T. The magnitude of electric field will be
Options
(a) 1.5×10³ NC⁻¹
(b) 2×10³ NC⁻¹
(c) 3×10³ NC⁻¹
(d) 1.33×10³ NC⁻¹
Correct Answer:
3×10³ NC⁻¹
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When a mass M is attached to the spring of force constant k,
- A gramophone record is revolving with an angular velocity ?. A coin is placed at
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- The thermo e.m.f. E in volts of a certain thermocouple is found to vary
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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Using v=EB,
we have , E = v B
E =(2×103)1.5
E =3×103NC−1