| ⇦ | 
| ⇨ |
A cell of emf E and internal resistance r supplies current for the same time t through external resistance R₁ and R₂ seperately. If the heat developed in both the cases is the same, then the internal resistance r will be
Options
(a) r=√R₁+R₂
(b) r=√R₁xR₂
(c) r=R₁+R₂/2
(d) r=1/R₁+1/R₂
Correct Answer:
r=√R₁xR₂
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The work done in which of the following processes is equal to the change in internal energy
- If the dimensions of a physical quantity are givenby Mᵃ Lᵇ Tᶜ, then the physical
- Light with an energy flux of 25×10⁴ Wm⁻² falls on a perfectly reflecting surface
- In a transistor, the value of βis 100, then the value of α will be
- A layer of glycerine of thickness 1 mm present between a large surface area of 0.1 m².
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The work done in which of the following processes is equal to the change in internal energy
- If the dimensions of a physical quantity are givenby Mᵃ Lᵇ Tᶜ, then the physical
- Light with an energy flux of 25×10⁴ Wm⁻² falls on a perfectly reflecting surface
- In a transistor, the value of βis 100, then the value of α will be
- A layer of glycerine of thickness 1 mm present between a large surface area of 0.1 m².
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply