| ⇦ | 
| ⇨ |
A body starts from rest with an acceleration of 2 m/s². After 5 second, the direction of acceleration reverses again for 5 second. The displacement is
Options
(a) 5 m
(b) 50 m
(c) 55 m
(d) 0 m
Correct Answer:
0 m
Explanation:
Body starts from rest
.·. u = 0, α = 2 m/s², t = 5 sec
S₁ = ut + 1/2 αt² = 0 х 5 + 1/2 х 2 х 5 х 5 = 25 m.
Now when the body reverse its acceleration
so S₂ = 10 х 5 – 1/2 х 2 х 5 х 5 = 50 – 25 = 25 m.
.·. Total distance travelled = 25 + 25 = 50 m.
Note : There is an error in the question. The distance being a scalar, it will be 50 m but displacement being vector, it was come back to the original position. Therefore it is zero.
Related Questions:
- The barrier potential of a p-n junction depends on
- In a uniform circular motion,
- Lumen is the unit of
- The voltage gain of an amplifier with 9% negative feedback is 10. The voltage gain
- A drum of radius R and mass M, rolls down without slipping along an inclined plane
Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply