| ⇦ | 
| ⇨ |
A body of mass 1.0 kg is falling with an acceleration of 10 ms⁻². Its apparent weight will be (g=10 ms⁻²)
Options
(a) 1.0 kg wt
(b) 2.0 kg wt
(c) zero
(d) 0.5 kg wt
Correct Answer:
zero
Explanation:
R = m (g – a) = m (10 – 10) = zero
This answer is an extension of the lift problem. Actually mg is the force acting on the mass m. As potential energy decreases, its kinetic energy increases as experienced. The question is not correct.
Related Questions: - The height of the dam, in an hydroelectric power station is 10 m. In order to generate
- If oxygen has root mean square velocity of C m/s, then root mean square velocity of H
- Two small spherical shells A and B are given positive charges of 9C and 4C
- If the binding energy of the nucleon in ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06 MeV
- In a water fall, the water falls from a height of 100 m. If the entire kinetic energy
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The height of the dam, in an hydroelectric power station is 10 m. In order to generate
- If oxygen has root mean square velocity of C m/s, then root mean square velocity of H
- Two small spherical shells A and B are given positive charges of 9C and 4C
- If the binding energy of the nucleon in ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06 MeV
- In a water fall, the water falls from a height of 100 m. If the entire kinetic energy
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply