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A body of mass 1.0 kg is falling with an acceleration of 10 ms⁻². Its apparent weight will be (g=10 ms⁻²)
Options
(a) 1.0 kg wt
(b) 2.0 kg wt
(c) zero
(d) 0.5 kg wt
Correct Answer:
zero
Explanation:
R = m (g – a) = m (10 – 10) = zero
This answer is an extension of the lift problem. Actually mg is the force acting on the mass m. As potential energy decreases, its kinetic energy increases as experienced. The question is not correct.
Related Questions: - Wave nature of light is verified by
- A charge of 40 µC is given to a capacitor having capacitance C=10 µF
- Two bodies of masses m₁ and m₂ and having velocities v₁ and v₂ respectively
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Wave nature of light is verified by
- A charge of 40 µC is given to a capacitor having capacitance C=10 µF
- Two bodies of masses m₁ and m₂ and having velocities v₁ and v₂ respectively
- Two bubbles A and B (A>B) are joined through a narrow tube. Then
- The electrons are emitted in the photoelectric effect from a metal surface
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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