⇦ | ![]() | ⇨ |
A body covers 200 cm in the first 2 seconds and 220 cm in the next 4 seconds. The velocity of the body at the end of the 7th second is
Options
(a) 10 cm/s
(b) 20 cm/s
(c) 5 cm/s
(d) 30 cm/s
Correct Answer:
10 cm/s
Explanation:
Let u and a be the initial velocity and uniform acceleration of the body.
Using kinematic equation, S = ut + (1/2) at²
.·. 200 = u × 2 + (1/2) a × 2²
⇒ 100 = u + a ——-(i)
Also 420 = 6u + (1/2) a × 6²
⇒ 70 = u + 3a ——-(ii)
Solving equation (i) and (ii), we get u = 115 cms⁻¹, a = -15 cms⁻²
Using equation, v = u + at .·. v = 115 + (-15) × 7 = 10 cms⁻¹
Related Questions:
- The Priniple of LASER action involves
- A body travels 200 cm in the first two seconds and 220 cm in the next 4 secs
- The damping force on an oscillator is directly proportional to the velocity.
- In a parallel plate capacitor with plate area A and charge Q, the force on one plate
- The transition from the state 3 n = 3 to n = 1 in a hydrogen like atom results
Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply