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A block of mass 10 kg is moving in X-direction with a constant speed of 10 ms⁻¹.It is subjected to a retarding force F=-0.1 x m⁻¹, during its travel from x=20m to x=30m.Its final kinetic energy will be
Options
(a) 475 j
(b) 450 j
(c) 275 j
(d) 250 j
Correct Answer:
475 j
Explanation:
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a=0.1x/m
=0.1/10=0.01 m/s2
v2=100-0.01[30x30-20x20]
=100-0.01x500
=100-5=95
final kinetic energy =1/2x10x95
=475J