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A black body is at 727⁰C. It emits energy at a rate which is proportional to
Options
(a) (1000)⁴
(b) (1000)²
(c) (727)⁴
(d) (727)²
Correct Answer:
(1000)⁴
Explanation:
According to Stefan’s law, E α T⁴
E α (t + 273)⁴ K [723⁰C = (727 + 273)K]
E α (727 + 273)⁴ K
E α (1000)⁴ K
Related Questions: - When radiation is incident on a photoelectron emitter,
- The binding energy of deutron is 2.2 MeV and that of ₂⁴He is 28 MeV.
- A thermocouple of negligible resistance produces an e.m.f. of 40 µV/⁰C in the linear range
- An α-particle moves in a circular path of radius 0.83 cm in the presence of a magnetic
- A body of weight W newton is at the surface of the earth.
Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When radiation is incident on a photoelectron emitter,
- The binding energy of deutron is 2.2 MeV and that of ₂⁴He is 28 MeV.
- A thermocouple of negligible resistance produces an e.m.f. of 40 µV/⁰C in the linear range
- An α-particle moves in a circular path of radius 0.83 cm in the presence of a magnetic
- A body of weight W newton is at the surface of the earth.
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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