Navigate

A bar magnet is hung by a thin cotton thread in a uniform horizontal magnetic field

A bar magnet is hung by a thin cotton thread in a uniform horizontal magnetic field and is in equillibrium state. The energy required to rotate it by 60⁰ is W. Now the torque required to keep the magnet in this new position is

Options

(a) W/√3
(b) √3W
(c) √3W/2
(d) 2W/√3

Correct Answer:

√3W

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

NEET2016
admin:

Related Questions

  1. The velocity of a particle at an instant is 10 ms⁻¹.After 3 s its velocity will become
  2. Fission of nuclei is possible because the binding energy per nucleon in them
  3. The kinetic energy needed to project a body of mass m from the surface of earth
  4. If the binding energy of the electron in a hydrogen atom is 13.6 eV, the energy
  5. Which is correct relation?