Navigate

A bar magnet is hung by a thin cotton thread in a uniform horizontal magnetic field

A bar magnet is hung by a thin cotton thread in a uniform horizontal magnetic field and is in equillibrium state. The energy required to rotate it by 60⁰ is W. Now the torque required to keep the magnet in this new position is

Options

(a) W/√3
(b) √3W
(c) √3W/2
(d) 2W/√3

Correct Answer:

√3W

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

NEET2016
admin:

Related Questions

  1. A thin and circular disc of mass M and radius R is rotating in a horizontal plane
  2. An object is placed 30 cm away from a convex lens of focal length 10 cm and a sharp
  3. The horizontal range and maximum height attained by a projectile are R and H,respectively
  4. A person can see clearly objects only when they lie between 50 cm and 400 cm from
  5. The de-Broglie wavelength of neutron in thermal equilibrium at temperature T is