A bar magnet is hung by a thin cotton thread in a uniform horizontal magnetic field and is in equillibrium state. The energy required to rotate it by 60⁰ is W. Now the torque required to keep the magnet in this new position is

Options

(a) W/√3
(b) √3W
(c) √3W/2
(d) 2W/√3

Correct Answer:

√3W

Explanation:

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