| ⇦ | 
| ⇨ |
A bar magnet having a magnetic moment of 2 x 10⁴JT⁻¹ is free to rotate in a horizontal plane. A horizontal magnetic field B = 6 x 10⁻⁴T exists in the space. The work done in taking the magnet slowly from a direction parallel to the field to a direction 60⁰ from the field is
Options
(a) 12 J
(b) 6 J
(c) 2 J
(d) 0.6 J
Correct Answer:
6 J
Explanation:
Work done
= MB (cos θ₁ – cos θ₂)
= MB (cos 0⁰ – cos 60⁰)
= MB (1 – 1/2) = 2 x 10⁴ x 6 x 10⁻⁴ /2 = 6 J
Related Questions: - What is the dimension of impedance?
- In cyclotron, for a given magnet, radius of the semicircle traced by positive ion
- The half-life of a radioactive substance is 30 min. The time (in minutes) taken
- The electric potential at a point (x,y,z) is given by V = – x²y – xz³ + 4.
- The impurity atoms with which pure silicon may be doped to make it a p-type
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- What is the dimension of impedance?
- In cyclotron, for a given magnet, radius of the semicircle traced by positive ion
- The half-life of a radioactive substance is 30 min. The time (in minutes) taken
- The electric potential at a point (x,y,z) is given by V = – x²y – xz³ + 4.
- The impurity atoms with which pure silicon may be doped to make it a p-type
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply