A 70 kg man stands in contact against the inner wall of a hollow cylindrical drum

A 70 Kg Man Stands In Contact Against The Inner Physics Question

A 70 kg man stands in contact against the inner wall of a hollow cylindrical drum of radius 3 m rotating about its vertical axis with 200 rev/min.The coefficient of friction between the wall and his clothing is 0.15.When the floor is suddenly removed, what is the minimum rotational speed of the cylinder to enable the man to remain stuck to the wall without falling (approximately)?

Options

(a) 5 rad/s
(b) 10 rad/s
(c) 15 rad/s
(d) 20 rad/s

Correct Answer:

5 rad/s

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

Related Questions:

  1. A ray of light is incident on a transparent glass slab of refractive index 1.62
  2. If the series limit of Lyman series for hydrogen atom is equal to the series limit
  3. A block of wood weighs 10 N and is resting on an inclined plane. The coefficient
  4. A man throws balls with the same speed vertically upwards one after the other
  5. A plumb line is suspended form a ceiling of a car moving with horizontal acceleration

Topics: Laws of Motion (103)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*