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300 mL of a gas at 27⁰C is cooled to -3⁰C at constant pressure. The final volume is
Options
(a) 350 L
(b) 270 mL
(c) 540 L
(d) 135 mL
Correct Answer:
270 mL
Explanation:
At constant pressure V₁ / T₁ = V₂ / T₂ (Charle’s law)
T₁ = 27°C = 27 + 273 = 300 K
T₂ = -3°C = -3 + 273 = 270K
V₂ = V₁T₂ / T₁ = (300 × 270) / 300 = 270 mL
Related Questions: - Which of the following is the coldest region
- The pH value of 0.1 M NaOH solution is (when there is a given reaction
- The correct order regarding the electronegetivity of hybrid orbitals of carbon is
- For adiabatic process,which is correct
- Which of the following alkyl halide is used as a methylating agent
Topics: States of Matter Gases and Liquids
(80)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following is the coldest region
- The pH value of 0.1 M NaOH solution is (when there is a given reaction
- The correct order regarding the electronegetivity of hybrid orbitals of carbon is
- For adiabatic process,which is correct
- Which of the following alkyl halide is used as a methylating agent
Topics: States of Matter Gases and Liquids (80)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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Acc to Charle’s law V1T2= V2 T1
V=300 ml
T1=27°C=27+273K=300K
V2=?
T2= 273-3°C=270K
V1T2= V2T1
300×270=V2×300
V2=270ml