| ⇦ | 
| ⇨ |
3 persons are initially at the 3 corners of an equilateral triangle whose side is equal to d. Each person now moves with a uniform speed v in such a way that the first moves directly towards the second and second directly towards the 3rd and 3rd directly towards the first. 3 persons will meet after a time equal to
Options
(a) d/v s
(b) 2d/3v s
(c) 2d/v√3 s
(d) d/v√3 s
Correct Answer:
2d/3v s
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions:
- If r be the distance of a point on the axis of a magnetic dipole from its centre
- A uranium nucleus ₉₂ U ²³⁸ emits an α-particle and a β-particle in succession.
- A device which converts electrical energy into mechanical energy is
- A heavy stone hanging from a massless string of length 15 m is projected
- A boat is sent across a river with a velocity of 8 km/h.If the resultant velocity
Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
D=UT+1/2AT2
U=0 (GIVEN)
D=1/2AT2
2D/A=T2
V2=U2+2AS (3PERSONS)
(U=0)
(3V)2==2AS
9V2/2D=A
2D/A=T2
2D*2D/9V2==T2
T==2D/3V