| ⇦ | 
| ⇨ |
3 persons are initially at the 3 corners of an equilateral triangle whose side is equal to d. Each person now moves with a uniform speed v in such a way that the first moves directly towards the second and second directly towards the 3rd and 3rd directly towards the first. 3 persons will meet after a time equal to
Options
(a) d/v s
(b) 2d/3v s
(c) 2d/v√3 s
(d) d/v√3 s
Correct Answer:
2d/3v s
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A uniform force of (3i + j) newton acfs on a particle of mass 2kg
- Which of the two have same dimensions?
- In nuclear fusion, two nuclei come together to form a large nucleus.
- The dimensions of mobility of charge carriers are
- The time period of a thin bar magnet in Earth’s magnetic field is T
Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A uniform force of (3i + j) newton acfs on a particle of mass 2kg
- Which of the two have same dimensions?
- In nuclear fusion, two nuclei come together to form a large nucleus.
- The dimensions of mobility of charge carriers are
- The time period of a thin bar magnet in Earth’s magnetic field is T
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
D=UT+1/2AT2
U=0 (GIVEN)
D=1/2AT2
2D/A=T2
V2=U2+2AS (3PERSONS)
(U=0)
(3V)2==2AS
9V2/2D=A
2D/A=T2
2D*2D/9V2==T2
T==2D/3V