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A source of light is placed at a distance of 50 cm from a photocell and the stopping potential is found to be V₀. If the distance between the light source and photocell is made 25 cm, the new stopping potential will be
Options
(a) 2V₀
(b) V₀ / 2
(c) V₀
(d) 4V₀
Correct Answer:
V₀
Explanation:
Since, stopping potential is independent of distance hence new stopping potential will remain unchanged i.e., new stopping potential = V₀.
Related Questions: - Alternating current is transmitted to distant places at
- A galvanometer of 50 Ω resistance has 25 divisions. A current of 4×10⁻⁴ A gives
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Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Alternating current is transmitted to distant places at
- A galvanometer of 50 Ω resistance has 25 divisions. A current of 4×10⁻⁴ A gives
- Application of Bernoulli’s theorem can be seen in
- A metal rod of length l cuts across a uniform magnetic field B with a velocity v.
- The potential energy of a simple harmonic oscillator when the particle is half way
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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