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A source of light is placed at a distance of 50 cm from a photocell and the stopping potential is found to be V₀. If the distance between the light source and photocell is made 25 cm, the new stopping potential will be
Options
(a) 2V₀
(b) V₀ / 2
(c) V₀
(d) 4V₀
Correct Answer:
V₀
Explanation:
Since, stopping potential is independent of distance hence new stopping potential will remain unchanged i.e., new stopping potential = V₀.
Related Questions: - If |A x B|= √3 A.B , then the value of |A + B| is
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Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If |A x B|= √3 A.B , then the value of |A + B| is
- Which one of the following statements is WRONG in the context of X-rays generated
- During negative β-decay
- A disc of radius 0.1 m is rotating with a frequency 10 rev/sec in a normal magnetic
- Consider a compound slab consisting of two different materials having equal thickness
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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