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When a Daniel cell is connected in the secondary circuit of a potentiometer, the balancing length is found to be 540 cm. If the balancing length becomes 500 cm when the cell is short circuited with 1 Ω, the internal resistance of the cell is
Options
(a) 0.08 Ω
(b) 0.04 Ω
(c) 1.45 Ω
(d) 1.08 Ω
Correct Answer:
0.08 Ω
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Resistances n, each r Ω, when connected in parallel give an equivalent resistance
- Across a metallic conductor of non-uniform cross-section, a constant potential
- An alternating voltage given as, V=100√2 sin100t V is applied to a capacitor
- A coil of self-inductance L is connected in series with a bulb B and an AC source
- What is the energy of photon whose wavelength is 6840 Å?
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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((Final length-initial length)/initial length )×resistence increased
((540-500)/500 )×1=40/500=0.08ohm