| ⇦ | 
| ⇨ |
A wire of a certain material is stretched slowly by ten percent. Its new resistance and specific resistance become respectively
Options
(a) both remain the same
(b) 1.1 times, 1.1 times
(c) 1.2 times, 1.1 times
(d) 1.21 times, same
Correct Answer:
1.21 times, same
Explanation:
Δl / l = 0.1 , Therefore, l = 1.1 but the area also decreases by 0.1.
mass = ρlA = Vρ. In l + In A = 1n mass.
.·. Δl / l = ΔA / A = 0 ⇒ Δl / l = -ΔA / A
Length increases by 0.1, resistance increases, area decreases by 0.1, then also resistance will increase. Total increase in resistance is approximately 1.2 times, due to increase in length and decrease in area. But specific resistance does not change.
Related Questions: - In vacuum, to travel distance d, light takes time t and in medium to travel distance
- A parallel plate capacitor of a capacitance 1 pF has seperation between the plates
- Copper of fixed volume V is drawn into wire of length l. When this wire is subjected
- If v is the speed of sound in air, then the shortest length of the closed pipe
- Watt hour mter measures
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In vacuum, to travel distance d, light takes time t and in medium to travel distance
- A parallel plate capacitor of a capacitance 1 pF has seperation between the plates
- Copper of fixed volume V is drawn into wire of length l. When this wire is subjected
- If v is the speed of sound in air, then the shortest length of the closed pipe
- Watt hour mter measures
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply