| ⇦ | 
| ⇨ |
If the binding energy of the electron in a hydrogen atom is 13.6 eV, the energy required to remove the electron from the first excited state of Li⁺⁺ is
Options
(a) 122.4 eV
(b) 30.6 eV
(c) 13.6 eV
(d) 3.4 eV
Correct Answer:
30.6 eV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The two ends of a metal rod are maintained at temperatures 100°C and 110°C.
- What is the energy released by fission of 1 g of U²³⁵?
- Work done by an external agent in separating the parallel plate capacitor is
- A small signal voltage V(t)=V₀ sin ωt is applied across an ideal capacitor C
- Two bullets are fired simultaneously, horizontally and with different speeds
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The two ends of a metal rod are maintained at temperatures 100°C and 110°C.
- What is the energy released by fission of 1 g of U²³⁵?
- Work done by an external agent in separating the parallel plate capacitor is
- A small signal voltage V(t)=V₀ sin ωt is applied across an ideal capacitor C
- Two bullets are fired simultaneously, horizontally and with different speeds
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply