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The wavelength of light emitted from second orbit to first orbit in a hydrogen atom is
Options
(a) 1.215×10⁻⁷ m
(b) 1.215×10⁻⁵ m
(c) 1.215×10⁻⁴ m
(d) 1.215×10⁻³ m
Correct Answer:
1.215×10⁻⁷ m
Explanation:
For hydrogen atom, energy = -(13.6 / n²) eV
Energy radiated = 13.6 [(1/1²) – (1/2²)] = [(13.6 × 3) / 4] eV
Energy = hc / λ = [(6.6 × 10⁻³⁴ × 3 × 10⁸) / λ × 1.6 × 10⁻¹⁹] eV
[(13.6 × 3) / 4] = [(6.6 × 10⁻³⁴ × 3 × 10⁸) / λ × 1.6 × 10⁻¹⁹]
λ = (6.6 × 3 × 4 × 10⁻²⁶) / (13.6 × 3 × 1.6 × 10⁻¹⁹) = 1.215 × 10⁻⁷ m
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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