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If in a L-R series circuit the power factor is 1/2 and R=100Ω, then the value of L is, when AC mains is used
Options
(a) πH
(b) √3/π H
(c) π/√3 H
(d) √2/π H
Correct Answer:
√3/π H
Explanation:
power factor, cos ɸ = 1 / 2 ⇒ ɸ = 60°
Therefore, tan 60° = ωL / R ⇒ √3 = (2πv × L) / 100
L = [(√3 × 100) / (2π × 50)] = (√3 / π) H
Related Questions: - An unpolarised beam of intensity I is incident on a pair of nicols making an angle
- A 100Ω resistance and a capacitor of 100Ω reactance are connected in series
- The magnetic moment has dimensions of
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Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An unpolarised beam of intensity I is incident on a pair of nicols making an angle
- A 100Ω resistance and a capacitor of 100Ω reactance are connected in series
- The magnetic moment has dimensions of
- The unit of specific conductivity is
- Two cells, having the same e.m.f. are connected in series through an external resistance
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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