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A body covers 200 cm in the first 2 seconds and 220 cm in the next 4 seconds. The velocity of the body at the end of the 7th second is
Options
(a) 10 cm/s
(b) 20 cm/s
(c) 5 cm/s
(d) 30 cm/s
Correct Answer:
10 cm/s
Explanation:
Let u and a be the initial velocity and uniform acceleration of the body.
Using kinematic equation, S = ut + (1/2) at²
.·. 200 = u × 2 + (1/2) a × 2²
⇒ 100 = u + a ——-(i)
Also 420 = 6u + (1/2) a × 6²
⇒ 70 = u + 3a ——-(ii)
Solving equation (i) and (ii), we get u = 115 cms⁻¹, a = -15 cms⁻²
Using equation, v = u + at .·. v = 115 + (-15) × 7 = 10 cms⁻¹
Related Questions: - When a mass M is attached to a spring of force constant K,
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Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When a mass M is attached to a spring of force constant K,
- The magnetic field in a certain region of space is given by B =8.35×10⁻² Î T.
- At which place, Earth’s magnetism becomes horizontal
- The diameter of the eye ball of a normal eye is about 2.5 cm. The power of the eye
- A light emitting diode(LED) has a voltage drop of 2 volt across it
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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