⇦ | ⇨ |
A galvanometer of resistance 50Ω is connected to a battery of 3 V along with a resistance of 2950 Ω in series. A full scale deflection of 30 divisions is obtained in the galvanometer. In order to reduce this deflection to 20 divisions, the resistance in series should be
Options
(a) 6050 Ω
(b) 4450 Ω
(c) 5050 Ω
(d) 5550 Ω
Correct Answer:
4450 Ω
Explanation:
I=3 / (50+2950) = 10⁻³ A
Current for 30 divisions=10⁻³ A
Current for 20 divisions=10⁻³ * 20/30
=2*10⁻³ / 3 Amperes
For the same deflection to obtain for 20 divisions let resistance added be R, therefore,
2*10⁻³ / 3 = 3 / (50+R)
(50+R) = 9 *10⁻³ / 2
(50+R) = 4500
Therefore R=4450Ω
Related Questions: - If a body is rolling on the surface, its total energy will be
- A disc of radius 0.1 m is rotating with a frequency 10 rev/sec in a normal magnetic
- An electric dipole placed in a non-uniform electric field experiences
- A 1 µA beam of protons with a cross-sectional area of 0.5 sq.mm is moving with a velocity
- A body is under stress F and has Young’s modulus Y, then the energy
Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If a body is rolling on the surface, its total energy will be
- A disc of radius 0.1 m is rotating with a frequency 10 rev/sec in a normal magnetic
- An electric dipole placed in a non-uniform electric field experiences
- A 1 µA beam of protons with a cross-sectional area of 0.5 sq.mm is moving with a velocity
- A body is under stress F and has Young’s modulus Y, then the energy
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply