| ⇦ |
| ⇨ |
A particle doing SHM has amplitude=4 cm and time period = 12 sec. The ratio between times taken by it in going from its mean position to 2 cm and from 2 cm to extreme position is
Options
(a) 1
(b) 1/3
(c) 1/4
(d) 1/2
Correct Answer:
1/2
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Maximum velocity of the photoelectron emitted by a metal is 1.8×10⁶ ms⁻¹.
- The value of Poisson’s ratio lies between
- If a magnet is suspended at an angle 30⁰ to the magnetic meridian, the dip needle
- A force F=ai+3j+6k is acting at a point r=2i-6j-12k. The value of α for
- A resistance R draws power P when connected to an AC source. If an inductance
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Maximum velocity of the photoelectron emitted by a metal is 1.8×10⁶ ms⁻¹.
- The value of Poisson’s ratio lies between
- If a magnet is suspended at an angle 30⁰ to the magnetic meridian, the dip needle
- A force F=ai+3j+6k is acting at a point r=2i-6j-12k. The value of α for
- A resistance R draws power P when connected to an AC source. If an inductance
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply