| ⇦ | 
| ⇨ |
Three particles A,B and C are thrown from the top of a tower with the same speed. A is thrown straight up, B is thrown straight down and C is thrown horizontally. They hit the ground with speed V(A),V(B) and V(C) respectively.
Options
(a) V(A)=V(B)=V(C)
(b) V(B)>V(C)>V(A)
(c) V(A)=V(B)>V(C)
(d) V(A)>V(B)=V(C)
Correct Answer:
V(A)=V(B)>V(C)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - An explosion breaks a rock into three parts in a horizontal plane
- The most stable particle in Baryon group is
- A beam of light consisting of red, green and blue colours is incident on a right
- A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped
- An electric motor operating on a 60 volt D.C supply draws a current of 10 amp.
Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An explosion breaks a rock into three parts in a horizontal plane
- The most stable particle in Baryon group is
- A beam of light consisting of red, green and blue colours is incident on a right
- A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped
- An electric motor operating on a 60 volt D.C supply draws a current of 10 amp.
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply