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A galvanometer coil has a resistance of 15 ohm and gives full scale deflection for a current of 4 mA. To convert it to an ammeter of range 0 to 6 A,
Options
(a) 10 mΩ resistance is to be connected in parallel to the galvanometer
(b) 10 mΩ resistance is to be connected in series with the galvanometer
(c) 0.1 Ω resistance is to be connected in parallel to the galvanometer
(d) 0.1 Ω resistance is to be connected in series with the galvanometer
Correct Answer:
10 mΩ resistance is to be connected in parallel to the galvanometer
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Given :-
G=15ohm Ig=4mA =0.004A.
I=6A. A shunt resistor of resistance S is to be connected in parallel with the galvanometer to convert it into an ammeter . The value of S is given by – S = Ig×G / I-Ig.
= 0.004 ×15 / 6-0.004. S= 0.06/5.996 = 0.01ohm =10m ohm.