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A block of mass 5 kg is moving horizontally at a speed of 1.5 m/s. A perpendicular force of 5 N acts on it for 4 sec. What will be the distance of the block from the point where the force started acting?
Options
(a) 6 m
(b) 8 m
(c) 10 m
(d) 2 m
Correct Answer:
10 m
Explanation:
Horizontal distance,x=ut ⇒1.5 x 4 = 6m
Vertical distance,y=(1/2)at² = (1/2)(F/m)t²
Two motions are in mutually perpendicular directions. Net displacement = √(6²+8²) = √(36+64) =√100 = 10m.
Related Questions: - An object is projected with a velocity of 20 m/s making an angle of 45⁰ with horizontal.
- A body is rolling down an inclined plane.If KE of rotation is 40% of KE in a translatory
- A boat of anchor is rocked by waves whose crests are 100 m apart and velocity
- A proton of mass 1.6×10⁻²⁷ kg goes round in a circular orbit of radius 0.10 m under
- An electron of mass m and a photon have same energy E. The ratio of de-Broglie
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An object is projected with a velocity of 20 m/s making an angle of 45⁰ with horizontal.
- A body is rolling down an inclined plane.If KE of rotation is 40% of KE in a translatory
- A boat of anchor is rocked by waves whose crests are 100 m apart and velocity
- A proton of mass 1.6×10⁻²⁷ kg goes round in a circular orbit of radius 0.10 m under
- An electron of mass m and a photon have same energy E. The ratio of de-Broglie
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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