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Radius of orbit of satellite of earth is R. Its kinetic energy is proportional to
Options
(a) 1/R
(b) 1/√R
(c) R
(d) 1/R³/²
Correct Answer:
1/R
Explanation:
Kinetic energy of the satellite=1/2mv₀²
v₀=√GM/R
Now, Putting the value of v₀, We get,
Kinetic energy=1/2m(√GM/R)²
=1/2 GMm/R
Therefore, Kinetic energy is proportional to 1/R.
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Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The kinetic energy of particle moving along a circle of radius R depends
- A jar is filled with two non-mixing liquids 1 and 2 having densities
- A particle is released from rest from a tower of height h, i.e,t₁ : t₂ : t₃ is
- Two spherical conductors A and B of radii 1 mm and 2 mm are separated by a distance
- A ball is dropped from a height of 20 cm. Ball rebounds to a height of 10cm
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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