| ⇦ | 
| ⇨ |
A car of mass m is moving on a level circular track of radius R. If µs represents the static friction between the road and tyres of the car, the maximum speed of the car in circular motion is given by :
Options
(a) √(µsmRg)
(b) √(Rg/µs)
(c) √(mRg/µs)
(d) √(µsRg)
Correct Answer:
√(µsRg)
Explanation:
For smoot h driving maximum speed of car v then
mv² / R = µsmg
v = √(µsRg)
Related Questions:
- The depth at which the effective value of acceleration due to gravity is g/4
- A common emitter amplifier has a voltage gain of 50, an input impedance of 100Ω
- If sink is at a temperature of -39⁰C and source at 0⁰C, then efficiency will be
- Three capacitors 3μF,6μF and 6μF are connected in series to a source of 120V.
- Cathode rays are produced when the pressure is of the order of
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply