| ⇦ |
| ⇨ |
A car of mass m is moving on a level circular track of radius R. If µs represents the static friction between the road and tyres of the car, the maximum speed of the car in circular motion is given by :
Options
(a) √(µsmRg)
(b) √(Rg/µs)
(c) √(mRg/µs)
(d) √(µsRg)
Correct Answer:
√(µsRg)
Explanation:
For smoot h driving maximum speed of car v then
mv² / R = µsmg
v = √(µsRg)
Related Questions: - In Young’s double slit experiment with sodium vapour lamp of wavelength
- A sound absorber attenuates the sound level by 20 dB. The intensity decreases
- The Bohr model of atoms
- A meter stick of mass 400 g is pivoted at one end and displaced through an angle 60°.
- Time period of oscillation of a magnet is 2 sec. When it is remagnetised
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In Young’s double slit experiment with sodium vapour lamp of wavelength
- A sound absorber attenuates the sound level by 20 dB. The intensity decreases
- The Bohr model of atoms
- A meter stick of mass 400 g is pivoted at one end and displaced through an angle 60°.
- Time period of oscillation of a magnet is 2 sec. When it is remagnetised
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply