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A car of mass m is moving on a level circular track of radius R. If µs represents the static friction between the road and tyres of the car, the maximum speed of the car in circular motion is given by :
Options
(a) √(µsmRg)
(b) √(Rg/µs)
(c) √(mRg/µs)
(d) √(µsRg)
Correct Answer:
√(µsRg)
Explanation:
For smoot h driving maximum speed of car v then
mv² / R = µsmg
v = √(µsRg)
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A galvanometer of resistance 50Ω is connected to a battery of 3 V along with a resistance
- A body of mass 120 kg and density 600 kg/m³ floats in water.
- The angular speed of earth, so that the object on equator may appear weightless
- The binding energy of deutron is 2.2 MeV and that of ₂⁴He is 28 MeV.
- The value of Poisson’s ratio lies between
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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