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A car of mass m is moving on a level circular track of radius R. If µs represents the static friction between the road and tyres of the car, the maximum speed of the car in circular motion is given by :
Options
(a) √(µsmRg)
(b) √(Rg/µs)
(c) √(mRg/µs)
(d) √(µsRg)
Correct Answer:
√(µsRg)
Explanation:
For smoot h driving maximum speed of car v then
mv² / R = µsmg
v = √(µsRg)
Related Questions: - In common base circuit of a transistor, current amplification factor is 0.95.
- The resistances of the four arms P,Q,R and S in a Wheatstone’s bridge
- Magnetic susceptibility of a material is given as
- An oscillator circuit consists of an inductance of 0. mH and a capacitor of 20 μF.
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In common base circuit of a transistor, current amplification factor is 0.95.
- The resistances of the four arms P,Q,R and S in a Wheatstone’s bridge
- Magnetic susceptibility of a material is given as
- An oscillator circuit consists of an inductance of 0. mH and a capacitor of 20 μF.
- A galvanometer of resistance 50Ω is connected to a battery of 3 V along with a resistance
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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