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The energy released in the fission of 1 kg of ₉₂U²³⁵ is (energy per fission = 200 MeV)
Options
(a) 5.1 x 10²⁶ eV
(b) 5.1 x 10²⁶ J
(c) 8.2 x 10¹³ J
(d) 8.2 x 10¹³ MeV
Correct Answer:
8.2 x 10¹³ J
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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- The electric field in a certain region is given by E=5i ̂-3ĵ kV/m. The potential
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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